SOLUTION: How do you Graph this slope Y=1/2x-3 Th

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Question 945978: How do you Graph this slope Y=1/2x-3
Th
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=%281%2F2%29%2Ax-3 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-8

y=%281%2F2%29%2A%28-8%29-3

y=-8%2F2-3 Multiply

y=-14%2F2 Add

y=-7 Reduce

So here's one point (-8,-7)




Now lets find another point

Plug in x=-6

y=%281%2F2%29%2A%28-6%29-3

y=-6%2F2-3 Multiply

y=-12%2F2 Add

y=-6 Reduce

So here's another point (-6,-6). Add this to our graph





Now draw a line through these points

So this is the graph of y=%281%2F2%29%2Ax-3 through the points (-8,-7) and (-6,-6)


So from the graph we can see that the slope is 1%2F2 (which tells us that in order to go from point to point we have to start at one point and go up 1 units and to the right 2 units to get to the next point) the y-intercept is (0,-3)and the x-intercept is (6,0)


We could graph this equation another way. Since b=-3 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,-3).


So we have one point (0,-3)





Now since the slope is 1%2F2, this means that in order to go from point to point we can use the slope to do so. So starting at (0,-3), we can go up 1 units



and to the right 2 units to get to our next point


Now draw a line through those points to graph y=%281%2F2%29%2Ax-3


So this is the graph of y=%281%2F2%29%2Ax-3 through the points (0,-3) and (2,-2)