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Question 94114: determine the equation of the line containing the points (0,2) and (2,0) when i did this problem i did y2-y1/x2-x1 and got 0-2/2-0 then got -2/0 then got 0 for my slope. then i chose the point (0,2) and got my answer y-2=0(x-0) so is that correct? if not what did i do wrong?
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! First lets find the slope through the points ( , ) and (,)
 Start with the slope formula (note: ) is the first point (,) and ) is the second point (,))
 Plug in  , , , (these are the coordinates of given points)
 Subtract the terms in the numerator  to get  . Subtract the terms in the denominator  to get
 Reduce
So the slope is
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Now let's use the point-slope formula to find the equation of the line:
------Point-Slope Formula------
 where  is the slope, and ) is one of the given points
So lets use the Point-Slope Formula to find the equation of the line
 Plug in , , and (these values are given)
 Distribute 
 Multiply and to get
 Add to both sides to isolate y
 Combine like terms and to get
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Answer:
So the equation of the line which goes through the points (,) and (,) is:
The equation is now in  form (which is slope-intercept form) where the slope is and the y-intercept is 
Notice if we graph the equation and plot the points (,) and (,), we get this: (note: if you need help with graphing, check out this solver)
 Graph of through the points (,) and (,)
Notice how the points lie on the line. This graphically verifies our answer.
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