SOLUTION: Please assist, Write the equation of a line perpendicular to the given line but passing through the given point. y = -4x - 5; point (0, -1)

Algebra ->  Linear-equations -> SOLUTION: Please assist, Write the equation of a line perpendicular to the given line but passing through the given point. y = -4x - 5; point (0, -1)      Log On


   



Question 931491: Please assist,
Write the equation of a line perpendicular to the given line but passing through the given point.
y = -4x - 5; point (0, -1)

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The slope of the line represented by y=-4x-5 is M=-4 .
The slope of a line perpendicular to a line of slope M} is m=-1%2FM ,
so the slope of the line you are looking for is
m=-1%2F%28%28-4%29%29=1%2F4 .
The x-coordinate of the point the line passes through is zero, meaning that the point is on the y-axis.
In other words that point is the y-intercept of the line.
The equation of a line can be written in the slope-intercept form as
y=mx%2Bb when the slope is m and the y-intercept is %22%28+0+%2C+b+%29%22 ,
so the equation you are looking for is
highlight%28y=%281%2F4%29x-1%29

NOTE: For this problem, the point given "happens to be" the y-intercept.
More generally:
A line of slope m , passing through a point P%28x%5BP%5D%2Cy%5BP%5D%29
can be represented by the equation y-y%5BP%5D=m%28x-x%5BP%5D%29 ,
and that is called a point-slope form of the equation.
So, the line you are looking for, passing through (0,-1) can be represented by the equation
y-%28-1%29=%281%2F4%29%28x-0%29 <---> y%2B1=%281%2F4%29x
The equation above is one of the infinite number of equations for the line you are looking for.
The more popular, one and only, slope-intercept form is the y=mx%2Bb form that you find when you "solve for y" :
y%2B1=%281%2F4%29x <---> y=%281%2F4%29x-1 .