SOLUTION: For what values of m will the parabola defined by equation: Y=(2m-6)x+(4-m)X2+11 open downward?

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Question 922422: For what values of m will the parabola defined by equation:
Y=(2m-6)x+(4-m)X2+11 open downward?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
the vertex form of a Parabola opening up(a>0) or down(a<0), y=a%28x-h%29%5E2+%2Bk
Y= (4-m)x^2 + (2m-6)x + 11
Will open downward when (4-m) < 0
0r
m > 4