SOLUTION: A small firm produces both AM and AM/FM car radios. The AM radios take 15 h
to produce, and the AM/FM radios take 20 h. The number of production hours is
limited to 300 h per wee
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-> SOLUTION: A small firm produces both AM and AM/FM car radios. The AM radios take 15 h
to produce, and the AM/FM radios take 20 h. The number of production hours is
limited to 300 h per wee
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Question 89538: A small firm produces both AM and AM/FM car radios. The AM radios take 15 h
to produce, and the AM/FM radios take 20 h. The number of production hours is
limited to 300 h per week. The plant’s capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 AM radios and at least 3 AM/FM radios be produced per week. Write a system of inequalities representing this situation. Then, draw a graph of the feasible region given these conditions, in which x is the number of AM radios and y the number of AM/FM radios
You can put this solution on YOUR website! A small firm produces both AM and AM/FM car radios.
Let x is the number of AM radios and y the number of AM/FM radios.
The AM radios take 15 hr to produce, and the AM/FM radios take 20 hr.
The number of production hours is limited to 300 hrs. per week.
Production EQUATION:
15x+20y <=300 hrs
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The plant’s capacity is limited to a total of 18 radios per week, and existing orders require that at least 4 AM radios and at least 3 AM/FM radios be produced per week.
4<=x<=18
3<=y<=18
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Write a system of inequalities representing this situation.
Then, draw a graph of the feasible region given these conditions,
Draw a vertical line at x=4 and at x=18.
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Cheers,
Stan H.
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