SOLUTION: You knew it was coming, didn’t you? Problem 22 asks you to graph the given function. Example 5 on p. 657 provides a good model to go by…. 22) f(x) = -2x – 5

Algebra ->  Linear-equations -> SOLUTION: You knew it was coming, didn’t you? Problem 22 asks you to graph the given function. Example 5 on p. 657 provides a good model to go by…. 22) f(x) = -2x – 5       Log On


   

Question 88864: You knew it was coming, didn’t you? Problem 22 asks you to graph the given function. Example 5 on p. 657 provides a good model to go by….
22) f(x) = -2x – 5

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Graphing Linear Equations
In order to graph y=-2%2Ax-5 we only need to plug in two points to draw the line

So lets plug in some points

Plug in x=-7

y=-2%2A%28-7%29-5

y=14-5 Multiply

y=9 Add

So here's one point (-7,9)




Now lets find another point

Plug in x=-6

y=-2%2A%28-6%29-5

y=12-5 Multiply

y=7 Add

So here's another point (-6,7). Add this to our graph





Now draw a line through these points

So this is the graph of y=-2%2Ax-5 through the points (-7,9) and (-6,7)


So from the graph we can see that the slope is -2%2F1 (which tells us that in order to go from point to point we have to start at one point and go down -2 units and to the right 1 units to get to the next point), the y-intercept is (0,-5)and the x-intercept is (-2.5,0) ,or (-5%2F2,0)


We could graph this equation another way. Since b=-5 this tells us that the y-intercept (the point where the graph intersects with the y-axis) is (0,-5).


So we have one point (0,-5)





Now since the slope is -2%2F1, this means that in order to go from point to point we can use the slope to do so. So starting at (0,-5), we can go down 2 units



and to the right 1 units to get to our next point


Now draw a line through those points to graph y=-2%2Ax-5


So this is the graph of y=-2%2Ax-5 through the points (0,-5) and (1,-7)