SOLUTION: The segment AB forms the base of an isosceles triangle, where A (4, 10) and B (-6, 12). The altitude of the triangle lies on the line y=mx+b. Find the value of B.
a)17
b)16.4
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-> SOLUTION: The segment AB forms the base of an isosceles triangle, where A (4, 10) and B (-6, 12). The altitude of the triangle lies on the line y=mx+b. Find the value of B.
a)17
b)16.4
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Question 886087: The segment AB forms the base of an isosceles triangle, where A (4, 10) and B (-6, 12). The altitude of the triangle lies on the line y=mx+b. Find the value of B.
a)17
b)16.4
c)16
d)15.8
e)15
*This is a Multiple Choice problem. Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website! You can use an altitude that lies on the line AB, since this line will intersect both the midpoint of AB and the vertex at the nonequal sides; because, this triangle is isosceles. You want the line PERPENDICULAR to line AB and which intersects the midpoint of AB. A sketch of the graph would help to understand.
MIDPOINT OF SEGMENT AB ; .
SLOPE OF AB
The line perpendicular must have slope and contain point (-1,11).
You do NOT want the value of B. You want the value of b for the line based on .
(