SOLUTION: Please help me to solve this,
For what values of K will the lines 2x-3y=5 and 4x=9+Ky be perpendicular?
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For what values of K will the lines 2x-3y=5 and 4x=9+Ky be perpendicular?
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Question 883830: Please help me to solve this,
For what values of K will the lines 2x-3y=5 and 4x=9+Ky be perpendicular? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Please help me to solve this,
For what values of K will the lines 2x-3y=5 and 4x=9+Ky be perpendicular?
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Put each equation in slope-intercept form:
y = (2/3)x - (5/3)
slope = 2/3
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y = (4/K)y - (9/K)
slope = 4/K
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Note:: For the lines to be perpendicular the product of the
slopes must be -1.
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(2/3)(4/K) = -1
8/(3K) = -1
3K = -8
K = -8/3
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Cheers,
Stan H.
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