SOLUTION: tickets to a class play cost $1.50 and .75 cents.is 520 tickets were sold for $555 how many of each kind were sold.
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-> SOLUTION: tickets to a class play cost $1.50 and .75 cents.is 520 tickets were sold for $555 how many of each kind were sold.
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You can put this solution on YOUR website! cheap ticket price 0.75
Let x = count of cheap tickets
expensive ticket price 1.50
Let y = count of higher price tickets
Account for tickets: x+y=520
Account for sales: 0.75x+1.5y=555
Elimination Method might be a good choice, but the choice is yours which method. Taking the sales equation and multiply by give the equivalent 5x+10y=3700, but this is simplifiable to
Now you could use the system:
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x+y=520
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x+2y=740
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This is an equivalent system to the initial ticket & sales account equations. Do you see what you can do using the elimination method to solve this simplified system?