SOLUTION: Write an equation in point-slope form of a line with a slope of –4 that goes through the point J(–5, 6)
Point Slope Form is y-y1=m(x-x1)
Where x1= -5 y1=6 m=-4
Therefore the
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-> SOLUTION: Write an equation in point-slope form of a line with a slope of –4 that goes through the point J(–5, 6)
Point Slope Form is y-y1=m(x-x1)
Where x1= -5 y1=6 m=-4
Therefore the
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Question 880023: Write an equation in point-slope form of a line with a slope of –4 that goes through the point J(–5, 6)
Point Slope Form is y-y1=m(x-x1)
Where x1= -5 y1=6 m=-4
Therefore the PSE is
y-6=-4(x-(-5))
y-6 =-4(x+5)
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