SOLUTION: Please help and explain how you came up with the answer. For some reason I continue to do something wrong when solving these particular problems. Write the equation of the line

Algebra ->  Linear-equations -> SOLUTION: Please help and explain how you came up with the answer. For some reason I continue to do something wrong when solving these particular problems. Write the equation of the line       Log On


   

Question 879587: Please help and explain how you came up with the answer. For some reason I continue to do something wrong when solving these particular problems.
Write the equation of the line perpendicular to 3x-y=6 and passing through (4,1). I am being asked to answer the equation in standard form.
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

line perpendicular to y+=+green%283%29x-6, m = 3

New line:  m = (-1/3) thru P(4,1)

***Using point-slope form, y+-+y%5B1%5D+=+m%28x+-+x%5B1%5D%29

  y -1 = (-1/3)(x-4)

   y = (-1/3)x + 4/3 + 1

   y = (-1/3)x + 7/3

or

 x + 3y = 7 in standard form

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Get to know standard form for a line.
Ax+By=C can be solved for y and then the slope can be seen. You will find that -%28A%2FB%29 is the slope. The slope of a line perpendicular would be the negative reciprocal of that, or %28B%2FA%29. What this means for the right hand member of standard form equation is either -Bx%2BAy or Bx-Ay.

The value of C will be different and depends on a point which the perpendicular line sought contains. Substitute this point for x and y and compute C.
In your example, 1%2Ax%2B3y=C.
Substitute the given needed point:
C=1%2A4%2B3%2A1
C=4%2B3
C=7
-
Equation x+3y=7 is perpendicular to 3x-y=6.