SOLUTION: The points (5,k) and (k, 3) lie on a line perpendicular to a line with a slope of 3/4. What is the value of k? So far I have arrived at {{{ 3/4 = (3-k)/(k-5)}}} using {{{ m=(Y2-Y1

Algebra ->  Linear-equations -> SOLUTION: The points (5,k) and (k, 3) lie on a line perpendicular to a line with a slope of 3/4. What is the value of k? So far I have arrived at {{{ 3/4 = (3-k)/(k-5)}}} using {{{ m=(Y2-Y1      Log On


   

Question 872292: The points (5,k) and (k, 3) lie on a line perpendicular to a line with a slope of 3/4. What is the value of k?
So far I have arrived at +3%2F4+=+%283-k%29%2F%28k-5%29 using +m=%28Y2-Y1%29%2F%28X2-X1%29 but i do not know how to proceed from there.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
the points are on the line perpendicular to a line with slope 3/4
so the slope of the line joining these points will be -4/3

+-4%2F3+=+%283-k%29%2F%28k-5%29
cross multiply
-4(k-5)=3(3-k)
-4k+20=9-3k
k=11