SOLUTION: find the slope intercept form (y=mx+b) of the equation for the line that satisfy the following: passes through (5, -9) and is perpendicular to the line whose equation is y=1/7x +4

Algebra ->  Linear-equations -> SOLUTION: find the slope intercept form (y=mx+b) of the equation for the line that satisfy the following: passes through (5, -9) and is perpendicular to the line whose equation is y=1/7x +4      Log On


   

Question 86854: find the slope intercept form (y=mx+b) of the equation for the line that satisfy the following:
passes through (5, -9) and is perpendicular to the line whose equation is y=1/7x +4
Answer by praseenakos@yahoo.com(507) About Me  (Show Source):
You can put this solution on YOUR website!
Question:

find the slope intercept form (y=mx+b) of the equation for the line that satisfy the following:
passes through (5, -9) and is perpendicular to the line whose equation is y=1/7x +4


Answer:

Equation of the required equation is given by the formula,

(y - y1) = m ( x- x1)

Here (x1, y1) = (5, -9)

Required line is perpendicular to +y+=+%281%2F7%29x+%2B4

Slope of this line is 1%2F7


So slope of the required line is = +-%287%2F1%29,
since these lines are perpendicular to each other, the product of their slopes should be -1


==> slope of the required line = -7


So equation of the rquired line,

==> ( y - (-5) = -7 ( x - 5)

==> y + 5 = -7x + 35


Subtract 5 from both sides.


==> y + 5 - 5 = -7x + 35 - 5

==> y = -7x + 30
Which is the required equation.


Hope you found the explanation useful.



Warm Regards.

Praseena.