SOLUTION: solve by cross multiplication method QUS: x is divided by a + y is divided by b is equal to a+b,this is first equation & x is divided by square of a + y is divided by square o

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Question 862167: solve by cross multiplication method
QUS: x is divided by a + y is divided by b is equal to a+b,this is first equation
& x is divided by square of a + y is divided by square of b is equal to two,
this is equation two

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
%28x%2F%28a%2By%29%29%2Fb=a%2Bb, your first equation;

x%2F%28a%2By%29%5E2%2Fb%5E2=2, your second equation.

Those already look crazy. Here is another try to understand:
x%2Fa%2By%2Fb=a%2Bb, your first equation;
Simplifying, bx%2Bay=ab%28a%2Bb%29;
x%2Fa%5E2%2By%2Fb%5E2=2, your second equation.
Simplifying, b%5E2%2Ax%2Ba%5E2y=2a%5E2b%5E2.
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Continuing with this, these equations are both linear in x and y. That is assuming if a and b are taken as constants.
System is:
--------------------
bx+ay=ab(a+b)
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b^2x+a^2y=a(ab)^2
--------------------

Maybe use Elimination Method.
b%2Abx%2Bb%2Aay=ab%5E2%28a%2Bb%29, as first equation.
%28b%5E2x%2Ba%5E2y%29-%28b%5E2x%2Baby%29=a%28ab%29%5E2-ab%5E2%28a%2Bb%29, subtracting first from second.
a%5E2y-aby=a%5E3%2Ab%5E2-ab%5E2%28a%2Bb%29, the x term has been "eliminated".
%28a%5E2-ab%29y=a%5E3b%5E2-ab%5E2%28a%2Bb%29
y=%28a%5E3b%5E2-ab%5E2%28a%2Bb%29%29%2F%28a%5E2-ab%29
highlight%28y=%28a%5E2b%5E2-b%5E2%28a%2Bb%29%29%2F%28a-b%29%29
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Next, to solve for x, you could either try elimination of y to solve for x, or you could try substituting what was just found for y into either system equation and solve for x.
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Here is an attempt substituting.
b%5E2x%2Ba%5E2y=a%28ab%29%5E2
x%2Ab%5E2=a%5E3b%5E2-a%5E2y
x=%28a%5E3b%5E2-a%5E2y%29%2F%28b%5E2%29=a%5E3-%28a%2Fb%29%5E2%2Ay
x=a%5E3-%28a%2Fb%29%5E2%28%28a%5E2b%5E2-b%5E2%28a%2Bb%29%29%2F%28a-b%29%29... and then a bit of further work to simplify this.
x=a%5E3-a%5E2%28a%5E2-ab%29%2F%28a-b%29
x=a%5E3-a%5E3%28a-b%29%2F%28a-b%29
x=a%5E3-a%5E3%2A1
highlight%28x=0%29-----Interesting result.