SOLUTION: Write an equation for the line that is parallel to the given line and that passes through the given point. y=(3/4)x-9; (-8, -18) A well detailed explanation would be highly a

Algebra ->  Linear-equations -> SOLUTION: Write an equation for the line that is parallel to the given line and that passes through the given point. y=(3/4)x-9; (-8, -18) A well detailed explanation would be highly a      Log On


   

Question 846118: Write an equation for the line that is parallel to the given line and that passes through the given point.
y=(3/4)x-9; (-8, -18)
A well detailed explanation would be highly appreciated so I can attempt problems like this with an understanding.
Found 2 solutions by Fombitz, lwsshak3:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Parallel lines have the same slope so the line would look like y=%283%2F4%29x%2Bb
Now use the point to solve for b.
y=%283%2F4%29x%2Bb
-18=%283%2F4%29%28-8%29%2Bb
-18=-6%2Bb
b=-12
highlight_green%28y=%283%2F4%29x-12%29

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write an equation for the line that is parallel to the given line and that passes through the given point.
y=(3/4)x-9; (-8, -18)
***
Standard form of an equation for a line: y=mx+b, m=slope, b=y-intercept (this is called the slope-intercept form)
For given equation:
y=(3/4)x-9
slope,m=3/4
..
For equation that passes through the given point(-8,-18)
slope,m=3/4 (lines parallel to each other have the same slope)
..
solve for b using given points(-8,-18)
y=mx+b
y=3x/4+b
sub given points:
-18=3*(-8)/4+b
-18=-24/4+b
-18=-6+b
b=-12
equation:y=(3/4)x-12