SOLUTION: a) Show that the point B (-3,-2) lies on the
circle defined by x^2+y^2=13.
b) Find an equation for the radius from the
origin O to point B.
c) Find an equation for the lin
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Linear-equations
-> SOLUTION: a) Show that the point B (-3,-2) lies on the
circle defined by x^2+y^2=13.
b) Find an equation for the radius from the
origin O to point B.
c) Find an equation for the lin
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Question 840202: a) Show that the point B (-3,-2) lies on the
circle defined by x^2+y^2=13.
b) Find an equation for the radius from the
origin O to point B.
c) Find an equation for the line that passes
through B and is perpendicular to OB. Found 2 solutions by Alan3354, ewatrrr:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! a) Show that the point B (-3,-2) lies on the
circle defined by x^2+y^2=13.
Sub -3 for x and -2 for y
-----------------------------
b) Find an equation for the radius from the
origin O to point B.
y = 2x/3
---------------
c) Find an equation for the line that passes
through B and is perpendicular to OB.
That's a line tangent at B
The slope is -3/2 (the negative inverse of the slope in b) above)
Also, the slope of a tangent line of a circle about the Origin is
-x/y
y+2 = (-3/2)(x + 3)
Hi,
a) Show that the point B (-3,-2) lies on the circle defined by x^2+y^2=13.
b) Find an equation for the radius from the origin O to point B. and
c) Find an equation for the line that passes through B and is perpendicular to OB.
Tangent Line has slope: -x/y 0r m = -3/2
y+2=(-3/2)(x+3),
