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Question 839787: find the equation of the line through the point (1,-6)and which is parallel to the line 3x-y+4=0
Answer by LinnW(1048)   (Show Source):
You can put this solution on YOUR website! Step one is solve 3x-y+4=0 for y
add y to each side
3x+4=y
In the template y = mx + b, m is the slope
so our slope = 3
We want a line with slope 3 going through (1,-6)
So we will substitute 3 for m, 1 for x and -6 for y in y = mx + b
-6 = 3(1) + b
-6 = 3 + b
add -3 to each side
-9 = b
So the equation parallel to 3x-y+4=0 is y=3x-9
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