SOLUTION: The line through (-3,0) and (0,9) The line through (4,0) and (o, -6) "Find The Equation of each line in slope-intercept form" ^Question

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Question 829775: The line through (-3,0) and (0,9)
The line through (4,0) and (o, -6)



"Find The Equation of each line in slope-intercept form"
^Question

Answer by MathLover1(20849) About Me  (Show Source):
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The line through (-3,0) and (0,9)
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-3, 0) and (x2, y2) = (0, 9).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%289-0%29%2F%280--3%29+=+3.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 3%2A-3+%2Bb+=+9. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0-3%2A-3+=+9.

y=(3)x + (9)

Your graph:





The line through (4,0) and (o, -6)
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (4, 0) and (x2, y2) = (0, -6).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-6-0%29%2F%280-4%29+=+1.5.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or 1.5%2A4+%2Bb+=+-6. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0-1.5%2A4+=+-6.

y=(1.5)x + (-6)

Your graph: