You can put this solution on YOUR website! What is an equation of a line that is perpendicular to y= 3/5x-2 and passes through point (5,-7)?
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Given line has slope = 3/5
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Perpendicular line must have slope = -5/3
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Form: y = mx + b
Solve for "b":
-7 = (-5/3)*5 + b
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-7 = -25/3 + b
b = (-21/3)+(25/3)
b = 4/3
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Equation:
y = (-5/3)x + (4/3)
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Cheers,
Stan H.
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