SOLUTION: two rectangles have the same unknown area
but the length of one is (6x+6)ft and width 4ft and the other has length 9ft and width 4xft. How do I fine what the variable x is?
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-> SOLUTION: two rectangles have the same unknown area
but the length of one is (6x+6)ft and width 4ft and the other has length 9ft and width 4xft. How do I fine what the variable x is?
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Question 825670: two rectangles have the same unknown area
but the length of one is (6x+6)ft and width 4ft and the other has length 9ft and width 4xft. How do I fine what the variable x is? Answer by jsmallt9(3758) (Show Source):
You can put this solution on YOUR website! The area of the first rectangle would be (6x+6)*4 = 24x+24.
The area of the second triangle would be 9*4x = 36x
We've been told that the two rectangles have the same area. So:
24x+24 = 36x
Now we just solve for x. Subtracting 24x from each side:
24 = 12x
Dividing by 12:
2 = x
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