SOLUTION: What is the maximum profit of: P(x)=+396x-2.1x^2-4000 thank you.

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Question 812745: What is the maximum profit of:
P(x)=+396x-2.1x^2-4000
thank you.
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
the vertex is the maximum profit
vertex x= (94.2857, P(x)=14668.6)
parabola
focus | (94.2857, 14668.5)
vertex | (94.2857, 14668.6)
semi-axis length | 0.119048
focal parameter | 0.238095
eccentricity | 1
directrix | y = 14668.7