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Question 807573: method of substitution to solve the system of linear equation
6a=7-b
6a=3-b
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! L1: 6a = 7 - b
L2: 6a = 3 - b
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L2: 6a = 3 - b
b = (3 - 6a)
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L1: 6a = 7 - b
6a = 7 - (3 - 6a)
6a = 7 - 3 + 6a
0 = 4
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Answer:
The lines L1 and L2 do not intersect.
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Check the answer by converting L1 and L2 to slope-intercept form: y = mx + b
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L1: 6a = 7 - b
a = 7/6 + (-1/6)b
a = (-1/6)b + 7/6
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L2: 6a = 3 - b
a = 3/6 + (-1/6)b
a = (-1/6)b + 3/6
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Now we can see that L1 and L2 have the same slope (-1/6).
But L1 and L2 have different y-intercepts (7/6 for L1 and 3/6 for L2).
So L1 and L2 are parallel lines that never intersect.
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