SOLUTION: Find an equation of the line Containing the point (2,-5) and parallel to the line 3x-5y= 9 I know I need to solve for "y", but my answer didn't go with the one my teacher got

Algebra ->  Linear-equations -> SOLUTION: Find an equation of the line Containing the point (2,-5) and parallel to the line 3x-5y= 9 I know I need to solve for "y", but my answer didn't go with the one my teacher got      Log On


   

Question 804464: Find an equation of the line
Containing the point (2,-5) and parallel to the line 3x-5y= 9
I know I need to solve for "y", but my answer didn't go with the one my teacher got
Found 2 solutions by erica65404, Alan3354:
Answer by erica65404(394) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for y
3x-5y=9
-5y=-3x%2B9
y=%283%2F5%29x-1.8
parallel lines have the same slope.
y=%283%2F5%29x%2Bb
plug in the point
2=%283%2F5%29%28-5%29%2Bb
2=-3%2Bb
b=5
your new equation
y=%283%2F5%29x%2B5

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find an equation of the line
Containing the point (2,-5) and parallel to the line 3x-5y= 9
----------------
find the slope of the line
3x-5y= 9
y = (3/5)x + something
slope = 3/5
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Use y = mx + b and the point to find b
-5 = (3/5)*2 + b
b = -31/5
--> y = 3x/5 - 31/5
or 3x - 5y = 31