SOLUTION: what is the slope of a line perpendicular to 4y=-8x+16

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Question 803289: what is the slope of a line perpendicular to 4y=-8x+16
Answer by lwsshak3(11628) About Me  (Show Source):
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what is the slope of a line perpendicular to 4y=-8x+16
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Rewrite given equation to standard form of equation for a line: y=mx+b,m=slope, b=y-intercept.
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4y=-8x+16
y=-2x+4
m=-2
slope of line perpendicular to given equation=1/2 (negative reciprocal)