Question 79242: Find the value of m in the equation y=mx+3, such that (-2,5) is on the graph. Found 2 solutions by tutorcecilia, Edwin McCravy:Answer by tutorcecilia(2152) (Show Source):
You can put this solution on YOUR website! y=mx+3 [slope-intercept equation of the line]
5=m(-2)+3 [substitute the values of x=-2 and y=5; and solve for the m-term]
5-3=-2m+3-3
2=-2m
2/-2=-2m/2
-1=m
.
check by plugging all of the values back into the original equation and solve]
y=mx+3 [original equatino]
(5)=(-1)(-2)+3
5=2+3
5=5 [checks out]
Find the value of m in the equation y=mx+3,
such that (-2,5) is on the graph.
Rule: If a point (1st number, 2nd number) is
on the graph of an equation containg a missing
letter OTHER than x or y, then you
substitute the 1st number for x and the
2nd number for y into the equation and
solve for that missing letter:
y = mx + 3
So we substitute -2 for x and 3 for y
5 = m(-2) + 3
5 = -2m + 3
Add 2m to both sides
2m + 5 = 3
Subtract 5 from both sides
2m = -2
Divide both sides by 2
m = -1
Edwin
