SOLUTION: Determine the x-intercept, the vertex, the direction of opening and the domain/range.
x=(x+6)(2x-5)
The only thing I know is that the y-intercept is -30 because I expanded it
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-> SOLUTION: Determine the x-intercept, the vertex, the direction of opening and the domain/range.
x=(x+6)(2x-5)
The only thing I know is that the y-intercept is -30 because I expanded it
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Question 776955: Determine the x-intercept, the vertex, the direction of opening and the domain/range.
x=(x+6)(2x-5)
The only thing I know is that the y-intercept is -30 because I expanded it into
x= 2x^2 + 7x - 30 and that it opens upward because 2x^2 is postive
I haven't done Math in months, so I'm completely stomped on these review questions Answer by solver91311(24713) (Show Source):
Your terminology is incorrect. -30 is NOT the -intercept. -30 is the -coordinate of the -intercept. The -intercept is the point
The -coordinate of the vertex of is given by . The -coordinate of the vertex is the value of the function at the vertex -value, or . Just plug in your numbers and do the arithmetic.
The -intercepts are the points and where and are the zeros of the function. These should be obvious because you started with the function already factored.
You are correct about the direction of opening.
This is a polynomial function so the domain is all real numbers. The range is the interval [)
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
