SOLUTION: determine the slope of the whose graph passes through the given pair then find the linear function in slope-intercept form. Draw the line 1. (5,0) and (0,6) 2.(-2,8) and (5,-3)

Algebra ->  Linear-equations -> SOLUTION: determine the slope of the whose graph passes through the given pair then find the linear function in slope-intercept form. Draw the line 1. (5,0) and (0,6) 2.(-2,8) and (5,-3)       Log On


   

Question 763780: determine the slope of the whose graph passes through the given pair then find the linear function in slope-intercept form. Draw the line
1. (5,0) and (0,6)
2.(-2,8) and (5,-3)
3. (1/2,5)(3/4,-3)
Answer by MathLover1(20850) About Me  (Show Source):
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1. (5,0) and (0,6)
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (5, 0) and (x2, y2) = (0, 6).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%286-0%29%2F%280-5%29+=+-1.2.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -1.2%2A5+%2Bb+=+6. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=0--1.2%2A5+=+6.

y=(-1.2)x + (6)

Your graph:




2.(-2,8) and (5,-3)
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, 8) and (x2, y2) = (5, -3).
Slope a is .
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -1.57142857142857%2A-2+%2Bb+=+4.85714285714286. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=8--1.57142857142857%2A-2+=+4.85714285714286.

y=(-1.57142857142857)x + (4.85714285714286)

Your graph:




3. (1/2,5)(3/4,-3)=(0.5,5)(0.75,-3)
Solved by pluggable solver: FIND EQUATION of straight line given 2 points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (0.5, 5) and (x2, y2) = (0.75, -3).
Slope a is a+=+%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29+=+%28-3-5%29%2F%280.75-0.5%29+=+-32.
Intercept is found from equation a%2Ax%5B1%5D%2Bb+=+y%5B1%5D, or -32%2A0.5+%2Bb+=+21. From that,
intercept b is b=y%5B1%5D-a%2Ax%5B1%5D, or b=5--32%2A0.5+=+21.

y=(-32)x + (21)

Your graph: