SOLUTION: Write an equation for the line that is parallel to the given line and passes through the given point. y = x + 8; (2, 16)
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-> SOLUTION: Write an equation for the line that is parallel to the given line and passes through the given point. y = x + 8; (2, 16)
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You can put this solution on YOUR website! Given line y = x + 8.
Principle 1: Any line expressed in the form has slope = m.
It has the y intercept (the point where it intersects the y axis as c.
(The more general form of a linear equation is ax + by = c, which can also be converted to the y = mx + c form.)
Principle 2: Lines parallel to each other have the same slope
Here the given line is already in the form y = mx + c
y = x + 8.
Slope of the given line = 1.
The parallel line also has slope 1 and passes through (2,16).
How can we express the second line also as y = mx + c?
m is the slope and c is the y intercept
We know m (which is 1), and we know one instance of x,y i.e. (2,16). We do not know the y intercept c.
Substituting for one value of x, y and m, we can find c.
or .
So, the equation to the second line is
:)