SOLUTION: The sum of a two digit number and the number obtained by interchanging the digits is 66. If the digits in the units place is 2 more than the digits in the tens place, find the numb

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Question 745446: The sum of a two digit number and the number obtained by interchanging the digits is 66. If the digits in the units place is 2 more than the digits in the tens place, find the number.
Answer by savvyhush23(50) About Me  (Show Source):
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The sum of a two digit number and the number obtained by interchanging the digits is 66. If the digits in the units place is 2 more than the digits in the tens place, find the number.
Let,
t+-+tens+place
u+-+unit+place
The two digit number is: 10t+%2B+u
interchanging the digit becomes: 10u+%2B+t
Their sum : %2810t+%2B+u%29+%2B+%2810u+%2B+t%29+=+66
11t+%2B+11u+=+66+ equation (1)
...If the digits in the units place is 2 more than the digits in the tens place...
u+=+t+%2B+2 equation (2)
Substitute (2) to (1);
11t+%2B+11%28t+%2B+2%29+=+66, solving t = 2 and u = 4
Therefore, the number is 10%282%29+%2B+%284%29=24