SOLUTION: Find the slope and y-intercept of the graph of each equation for: {{{(2/3)*x + (1/6)*y =2}}}

Algebra ->  Linear-equations -> SOLUTION: Find the slope and y-intercept of the graph of each equation for: {{{(2/3)*x + (1/6)*y =2}}}      Log On


   

Question 74: Find the slope and y-intercept of the graph of each equation for:
%282%2F3%29%2Ax+%2B+%281%2F6%29%2Ay+=2
Found 2 solutions by wynona, KMST:
Answer by wynona(4) About Me  (Show Source):
You can put this solution on YOUR website!
you have to change the equation so that y is left alone in the left side. To do that, move x to the right
%281%2F6%29%2Ay=2-%282%2F3%29%2Ax
multiply by 6
y+=+12+-+4x
Here's the graph:
graph%28+200%2C+300%2C+-5%2C+5%2C+-10%2C+10%2C+12-4x%29
to find the x intercept, at point y = 0, you have to solve for x:
0 = 12 - 4x. Solve it using the calculator on this site.

Answer by KMST(5484) About Me  (Show Source):
You can put this solution on YOUR website!
The slope is the coefficient of x in y=12-4x ,
so slope=highlight%28-4%29 .
The y-intercept is the value of y at the point the line crosses the y-axis.
The y- axis is the line x=0 ,
and substituting 0 for x in y=12-4x we get y=12 ,
the independent term in y=12-4x ,
so y-intercept=highlight%2812%29 .