SOLUTION: find the equation of the line in slope intercept form that is perpendicular to y=-1/2x+6 and passes through (3,-1). I sort of understand how to do this, but I'm stuck. Any help

Algebra ->  Linear-equations -> SOLUTION: find the equation of the line in slope intercept form that is perpendicular to y=-1/2x+6 and passes through (3,-1). I sort of understand how to do this, but I'm stuck. Any help      Log On


   

Question 731650: find the equation of the line in slope intercept form that is perpendicular to y=-1/2x+6 and passes through (3,-1).
I sort of understand how to do this, but I'm stuck. Any help with how you accomplished to answer this problem would highly appreciated! Thank you very much in advance! :)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+y+=+%28-1%2F2%29%2Ax+%2B+6+
The slope is +m+=+-1%2F2+
Any line perpendicular to this line has slope
+m%5B1%5D+=+-1%2Fm+
+m%5B1%5D+=+-1%2F%28-1%2F2%29+
+m%5B1%5D+=+2+
Use the point-slope formula
(3,-1)
+%28+y+-%28-1%29+%29+%2F+%28+x+-+3+%29+=+2+
+y+%2B+1+=+2%2A%28+x+-+3+%29+
+y+%2B+1+=+2x+-+6+
+y+=+2x+-7+ answer
-------------
check:
(3,-1)
+y+=+2x+-7+
+-1+=+2%2A3+-7+
+-1+=+6+-+7+
+-1+=+-1+
OK