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Question 720003: There is this question on my homework and it says: write and equation in standard form of the line that passes through (7,2) and has a y- intercept of -4
I know that standard form is Ax=By=C and i'm thinking that you would make it (7,2) (0,4) and then it would go into Y2-Y1/X2-X1 form. And end up with -6/-7 and now I and don't know what to do from here.
Found 2 solutions by Alan3354, richwmiller:
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! There is this question on my homework and it says: write and equation in standard form of the line that passes through (7,2) and has a y- intercept of -4
I know that standard form is Ax=By=C [it's Ax + By = C]and i'm thinking that you would make it (7,2) (0,4) and then it would go into Y2-Y1/X2-X1 form. And end up with -6/-7 and now I and don't know what to do from here.
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The points are (7,2) and (0,-4)
slope m = diffy/diffx = -6/-7 = 6/7
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You have the slope and the y-intercept, --> eqn is
y = (6/7)x + 4 (slope-intercept form)
Multiply by 7
7y = 6x + 28
6x - 7y = -28 (standard form)
Answer by richwmiller(17219)  (Show Source):
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