SOLUTION: Need help please Find the slope-intercept form of the line satisfying the given conditions parallel to y = 3x + 1, passing through (0,0) Have to show work Thank you

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Question 710756: Need help please
Find the slope-intercept form of the line satisfying the given conditions
parallel to y = 3x + 1, passing through (0,0)
Have to show work
Thank you

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
The slope-intercept form of the equation of a line is
y=mx%2Bb where the constant m is the slope,
and b is the intercept, the y-coordinate of the point where the line crosses the y-axis.
y+=+3x+%2B+1 is a line with slope highlight%28m=3%29 that crosses the y-axis at (0,1).
The slope is the "steepness" of the line, the increase in y as x increases by 1.
With a slope of 3, and starting from point (0,1) with x=0, and y=1,
increasing x to x=1, we get to the point with y=1+3=4, point (1,4).
From there, increasing x by 1 to x=2, we get to the point with y=4+3=7, point (2,7).
Parallel lines have the same slope, and (0,0) would be the point where the new line crosses the y-axis,
with y-coordinate=0, so highlight%28b=0%29 and
highlight%28y=3x%2B0%29 or highlight%28y=3x%29 is your answer.