SOLUTION: What are 5 points that satisfy the equation 5y+3x=-13 ?

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Question 708695: What are 5 points that satisfy the equation 5y+3x=-13 ?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
In theory, you could give either variable a value and solve for the other variable to get one point.
You would do it again for each additional point.

Or you could solve for one variable as a function of the other,
and get a formula:
5y%2B3x=-13 --> 5y=-3x-13 --> y=-%283x%2B13%29%2F5
For any value of x, that formula makes it easy to calculate the corresponding value for y.
Examples:
x=0 --> y=-%283%2A0%2B13%29%2F5 --> y=-13%2F5 gives you point (0,-13/5)
x=1 --> y=-%283%2A1%2B13%29%2F5 --> y=-%283%2B13%29%2F5 --> y=-16%2F5 gives you point (0,-16/5)

However, for this equation, with those coefficients in front of x and y,
you will end up with a lot of fractions, and may not like the results,
especially if you need to use those points for a graph.
If you want an integer value for y you need 3x%2B13 to be a multiple of 5,
and since 3x%2B13=3x%2B3%2B10=3%28x%2B1%29%2B5%2A2 you would want x%2B1 to be a multiple of 5,
like x%2B1=5 --> x=4
x=4 --> y=-%283%2A4%2B13%29%2F5 --> y=-%2812%2B13%29%2F5 --> y=-25%2F5 --> y=-5 gives you point (4,-5).

If you do not need to "show your work" you could get additional points easily using a graph,
without further calculations.

If you need or want to keep calculating,
increasing or decreasing x by 5 you will keep getting x%2B1 to be a multiple of 5,
and will keep getting integers for y.
x=9 gives you (9,-8)
x=-1 gives you (-1,-2)

GETTING ADDITIONAL POINTS FROM A GRAPH:
Once you have one point of the line, you can plot it on a graph,
and then you can use the slope of the line to place more points on the graph.
(If you do not need your graph, you may be able to get the same result adding numbers in your head,
or counting on your fingers).
From 5y%2B3x=-13, we could solve for y to get y=-%283x%2B13%29%2F5,
which made it easy to calculate one point.
We can go further to the highlight%28slope-intercept%29 form of the equation
y=-%283x%2B13%29%2F5 --> highlight%28y=%28-3%2F5%29x-13%2F5%29
where the coefficient of the x is the slope of the line.
Going from one point in the line to another point in the line,
the slope is the change in y divided by the change in x.
A slope of -3%2F5 means that
an increase of 5 units in x corresponds to
an increase of -3 units (meaning a decrease of 3 units) in y.
We use that fact to go from one point to the next on the graph.

We move 5 units to the right (an increase of 5 for x)
and 3 units down (decrease of 3 for y) to mark the next point.
We can also reverse direction, decreasing x by 5, while increasing y by 3.
So after calculating (4,-5) as a first point, we could go to (9,-8) and (14,-11).
Reversing direction we could go to (-1,-2) and to (-6,1).
Without graphing:
I would just make a table for the x and y values and put the first point I calculate on the table.
In this case, I would put x=4, y=-5 in the middle.
Then I would fill the x values counting by 5's up and down,
and the y values counting by -3 (counting by 3 in the other direction):