Question 701328: Show that the triangle with vertices (-5,2), (-2,5), and (5,-2) is a right angle. THANKS
Answer by MathLover1(20849)   (Show Source):
You can put this solution on YOUR website! first find the equation of the line passing through ( , ) and ( , )
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-5, 2) and (x2, y2) = (-2, 5).
Slope a is  .
Intercept is found from equation  , or  . From that,
intercept b is  , or  .
y=(1)x + (7)
Your graph:
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than find the equation of the line passing through (,) and (,)
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-5, 2) and (x2, y2) = (5, -2).
Slope a is  .
Intercept is found from equation , or  . From that,
intercept b is , or  .
y=(-0.4)x + (0)
Your graph:
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than find the equation of the line passing through (,) and (,)
| Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (-2, 5) and (x2, y2) = (5, -2).
Slope a is  .
Intercept is found from equation , or  . From that,
intercept b is , or  .
y=(-1)x + (3)
Your graph:
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now graph all three lines together:
 .........a slope is 
 .........a slope is 
 .........a slope is  which is negative reciprocal of ;  ...so, the line and are perpendicular to each other
if two of lines perpendicular to each other, and three intersecting line form a triangle, triangle is a right angle triangle
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