SOLUTION: find the equation of a line perpendicular to 3y=24 and passing through (-7, 11)

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Question 700324: find the equation of a line perpendicular to 3y=24 and passing through (-7, 11)
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
+3y=24
+y=24%2F3
+y=8........line parallel to x-axis, has y-intercept+of+%7B%7B%7B8 and slope m=0

the equation of a line perpendicular to +y=8 and passing through (-7, 11) has to have a slope negative reciprocal of m=0 which is m%5B1%5D=-1%2F0 and anything divided by 0 is undefined; so, the line is vertical
now we need to find the equation of a vertical line passing through (-7, 11)
So the perpendicular slope is undefined (m%5B1%5D=-1%2F0)
since the unknown line goes through (-7, 11), we can find the equation by plugging in this info into the point-slope formula
Point-Slope Formula:
y-y%5B1%5D=m%5B1%5D%28x-x%5B1%5D%29
y-y%5B1%5D%2Fm%5B1%5D=x-x%5B1%5D
%28y-11%29%2F1%2F0=x-%28-7%29
%28y-11%290=x%2B7
0=x%2B7
-7=x.........vertical line