SOLUTION: Write an equation of the line, in the form y = mx + b, that is parallel to the line 2x + 3y = 12, and passes through the origin.
Thank you so much for your help
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-> SOLUTION: Write an equation of the line, in the form y = mx + b, that is parallel to the line 2x + 3y = 12, and passes through the origin.
Thank you so much for your help
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Question 698789: Write an equation of the line, in the form y = mx + b, that is parallel to the line 2x + 3y = 12, and passes through the origin.
Thank you so much for your help Answer by Simnepi(216) (Show Source):
You can put this solution on YOUR website! The form y = mx + b gives the equation of a straight line where m is the slope of the line(the gradient) and b is the intercept of the line and the y axis.
All lines with the same gradient (i.e. the same number in front of the x) are parallel.
First, let's rearrange your line equation into the correct form of y = mx + b
2x + 3y = 12
take the x term across the equals sign (and change its sign as we do so)
3y = -2x + 12
Now divide by 3 (across the whole equation) to get rid of the 3y and just leave y
so
y = x + 4
Now we can find the equation of the new line.
The line we want to find has a gradient of , (remember? parallel lines have the same gradient!)
The intercept of the line we want is at (0,0) the origin. so the y intercept = 0
writing the whole equation of the line we want ......
y = x (you could write +0 but there really is no point!)
