Question 697440: (1)Factor.
4x^2+33x+35
(2)Factor.
4x^2-25x-56
(3)Factor.
6x^2-53x+40
(4)Factor.
y^2-64
(5)Factor.
x^2+16x+64 Found 2 solutions by Alan3354, MathLover1:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! (1)Factor.
4x^2+33x+35
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It's (ax + b)*(cx + d)
a, b, c & d are positive.
ac = either 1*4 oe 2*2
bd = either 1*35 or 5*7
Try all possibilities, find the one that works.
I can do it, but that won't help you do it.
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(2)Factor.
4x^2-25x-56
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The signs of c & d are opposite.
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(3)Factor.
6x^2-53x+40
The signs of c & d are both negative.
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(4)Factor.
y^2-64
It's a difference of 2 squares.
a^2-b^2 = (a-b)*(a+b)
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(5)Factor.
x^2+16x+64
Both ends are squares.
