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Question 697102: Find the equation of line passing through the point of intersection of the lines y=x and x+y=6 and which is perpendicular to 3x+6y=12
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! Find the equation of line passing through the point of intersection of the lines y=x and x+y=6 and which is perpendicular to 3x+6y=12
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y=x
x+y=6
..
x+x=6
2x=6
x=3
y=3
point of intersection: (3,3)
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Given line
3x+6y=12
6y=-3x+12
y=-3x/6+12/6
y=-x/2+2
slope,m=-1/2
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slope of line perpendicular to slope of given line=2 (negative reciprocal)
equation:
y=mx+b
y=2x+b
solve for b using coordinates of the point of intersection(3,3)
3=2*3+b
b=-3
Equation: y=2x-3 (ans.)
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