|
Question 696957: parallel and perpendicular lines
i need to put my answer into slope - intercept form,y= mx+b form
find the equation of the parallel line that passes thru the given information
Problem
m=3/2 thru (2,6)
I come up up with y-6=2/3(x-2) But i dont think this is right
now i am stumped on these three problems
i need help with
m = -4 thru (-2,3)
and my other problem m=1/3 thru (-1,3)
also m=1/4 thru (2,-4)
thank you for your help i am so mixed up i try and i get it backwards
Found 2 solutions by MathLover1, lwsshak3:
Answer by MathLover1(20849)   (Show Source):
You can put this solution on YOUR website! given:
 thru ( , )
| Solved by pluggable solver: FIND a line by slope and one point |
What we know about the line whose equation we are trying to find out:
- it goes through point (2, 6)
- it has a slope of 1.5
First, let's draw a diagram of the coordinate system with point (2, 6) plotted with a little blue dot:
Write this down: the formula for the equation, given point  and intercept a, is
 (see a paragraph below explaining why this formula is correct)
Given that a=1.5, and  , we have the equation of the line:
Explanation: Why did we use formula  ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point ( ,  ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (, ):  Here, we know a, , and , and do not know b. It is easy to find out:  . So, then, the equation of the line is:  .
Here's the graph:
|
Answer by lwsshak3(11628)  (Show Source):
You can put this solution on YOUR website! Standard form of equation for a straight line: y=mx+b, m=slope, b=y-intercept
m=3/2 thru (2,6)
equation: y=3x/2+b
solve for b using coordinates of given point
6=3*2/2+b
b=6-3=3
equation: y=3x/2+3
use this same method to solve the following 3 problems:
..
m = -4 thru (-2,3)
m=1/3 thru (-1,3)
m=1/4 thru (2,-4)
|
|
|
| |
