SOLUTION: What is an equation in slope-intercept form of the line that passes through (6, 10) and is parallel to the graph of y-=1/3x-1?

Algebra ->  Linear-equations -> SOLUTION: What is an equation in slope-intercept form of the line that passes through (6, 10) and is parallel to the graph of y-=1/3x-1?      Log On


   



Question 694810: What is an equation in slope-intercept form of the line that passes through (6, 10) and is parallel to the graph of y-=1/3x-1?
Found 2 solutions by stanbon, Ave:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
What is an equation in slope-intercept form of the line that
passes through (6, 10) and is parallel to the graph of y-=1/3x-1?
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The given equation has slope = 1/3
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The desired equation must have slope = 1/3 and y = 10 when x = 6
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10 = (1/3)(6) + b
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b = 8
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Equation:
y = (1/30x + 8
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Cheers,
Stan H.

Answer by Ave(106) About Me  (Show Source):
You can put this solution on YOUR website!
y-10=1/3(x-6) use point slope form(keep same slope for parallel)
3y-30=x-6 multiply both sides by 3 to get rid of fraction, add 30 to both sides
3y=x+24 divide by 3
y=%281%2F3%29x%2B8 <-slope intercept form