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Question 685360: Find the equation of the line through the y-intercept of y = x^4 – 3x^5 – 8 + x^2 and the x-intercept of y = 2x – 18.
If anyone can explain how to do this that would be awesome! I'm so confused. Thanks!
Found 2 solutions by Edwin McCravy, josmiceli:
Answer by Edwin McCravy(20055)   (Show Source):
You can put this solution on YOUR website!
To find the y intercept of y = x^4 – 3x^5 – 8 + x^2, substitute x=0 and
solve for y
y = 0^4 – 3(0)^5 – 8 + (0)^2
y = 0 - 0 - 8 + 0 =
y = -8
So the y intercept of that graph is (x,y) = (0,-8)
To find the y intercept of y = 2x – 18, substitute y=0 and
solve for x
y = 2x – 18
0 = 2x - 18
-2x = -18
x = 9
So the x intercept of that graph is (x,y) = (9,0)
So now the problem becomes:
Find the equation of the line which passes through the
two points (0,-8) and (9,0)
The slope is given by the formula:
m = 
m = 
m = 
So the y intercept of that graph is (x,y) = (0,-8),
so b = -8.
We can just use y = mx + b and get
y = x - 8
Edwin
Answer by josmiceli(19441)  (Show Source):
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