SOLUTION: find the equation of the line that passes through (-5,1) (2,1) In the form y=mx + b.....? step 1:m=y2-y1 1-1 0 step 2: y-y1=m(x-x1) i will use (2,1) y-1=0(x-2)

Algebra ->  Linear-equations -> SOLUTION: find the equation of the line that passes through (-5,1) (2,1) In the form y=mx + b.....? step 1:m=y2-y1 1-1 0 step 2: y-y1=m(x-x1) i will use (2,1) y-1=0(x-2)       Log On


   

Question 680136: find the equation of the line that passes through (-5,1) (2,1) In the form y=mx + b.....?
step 1:m=y2-y1 1-1 0 step 2: y-y1=m(x-x1) i will use (2,1) y-1=0(x-2)
x2-x1 2-(-5) 7 7

now Im stuck ... please help me

Answer by ReadingBoosters(3246) About Me  (Show Source):
You can put this solution on YOUR website!
%281-1%29%2F%28-5-2%29+=+0%2F-7+=+0
...
0 slope means it will be a horizontal line, which is why both points have the y value as 1.
...
y - 1 = 0(x- -5)
y - 1 = 0(x+5)
y-1=0
highlight_green%28y+=+1%29 --> this is the equation for the line
...
graph%28300%2C200%2C-10%2C10%2C-10%2C10%2C1%29
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