Question 678733: what is th slope of the line that passes through (6,-7) and (4,-8)
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! Two generic points that define a straight line are (x1, y1) and (x2, y2)
In this case, (x1, y1) = (6, -7), which means x1=6 and y1=-7
and (x2, y2) = (4, -8), which means x2=4 and y2=-8
So x1=6, y1=-7, x2=4, and y2=-8.
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Now use the slope formula
m = (y2-y1)/(x2-x1)
m = (-8-(-7))/(4-6)
m = (-8+7)/(4-6)
m = (-1)/(-2)
m = 1/2
So the slope of the line that passes through the two points is 1/2
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