SOLUTION: A jar filled with change is holding 5.45 and has 41 coins. There are nickles dimes and quarters. If we remove the nickles, the remaining coins have a value of 4.55. How many typ
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-> SOLUTION: A jar filled with change is holding 5.45 and has 41 coins. There are nickles dimes and quarters. If we remove the nickles, the remaining coins have a value of 4.55. How many typ
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Question 666034: A jar filled with change is holding 5.45 and has 41 coins. There are nickles dimes and quarters. If we remove the nickles, the remaining coins have a value of 4.55. How many type of each coin were there originally? Please set up a system of 3 equations and solve to answer this question. Please show work. Found 2 solutions by vleith, josmiceli:Answer by vleith(2983) (Show Source):
You can put this solution on YOUR website! Let n,d and q be the number of nickels, dimes and quarters respectively.
You are told
Thus
Check you answer.
Do 8 dimes and 15 quarters total to 455
You can put this solution on YOUR website! Let = number of nickels
Let = number of dimes
Let = number of quarters
---------------------------
given:
(1)
(2)
(3)
----------------------
Multiply both sides of (1) by 5 and
subtract (1) from (2)
(2)
(1)
Multiply both sides by
Subtract (3) from this
and
(3)
(3)
(3)
(3)
and
(1)
(1)
(1)
(1)
The number of nickels is 18
The number of dimes is 8
The number of quarters is 15
check:
(2)
(2)
(2)
(2)
OK
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