SOLUTION: if a ball is thrown directly upward with a velocity of 40 ft/sec, its height (in feet) after t seconds is given by the function: h(t)=-16t^2+40t
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-> SOLUTION: if a ball is thrown directly upward with a velocity of 40 ft/sec, its height (in feet) after t seconds is given by the function: h(t)=-16t^2+40t
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Question 664926: if a ball is thrown directly upward with a velocity of 40 ft/sec, its height (in feet) after t seconds is given by the function: h(t)=-16t^2+40t Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! if a ball is thrown directly upward with a velocity of 40 ft/sec, its height (in feet) after t seconds is given by the function: h(t)=-16t^2+40t
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That's true.
