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Question 664380: find the equation of the line with x-intercept 4 and y-intercept 8
Found 3 solutions by Alan3354, MathLover1, ReadingBoosters: Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! find the equation of the line with x-intercept 4 and y-intercept 8
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For intercepts (A,0) & (0,B), it's
Bx + Ay = A*B
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8x + 4y = 32
2x + y = 8
Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!
given:
and
so, you are given these two points: ( , ) and ( , )
now we can find the equation of a line passing through these two points:
Solved by pluggable solver: FIND EQUATION of straight line given 2 points |
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (4, 0) and (x2, y2) = (0, 8).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .
y=(-2)x + (8)
Your graph:

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so, the equation of the line with and is

Answer by ReadingBoosters(3246) (Show Source):
You can put this solution on YOUR website! Using (4,0) and (0,8)
the slope is determined as
(rise) 8-0 / (run) 0 - 4
8/-4 = -2
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Given y intercept and calculating slope we have the linear equation
y = -2x + 8
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Check
y = -2(4) + 8; y = 0
y = -2(0) + 8; y = 8
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-Reading Boosters
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