SOLUTION: Find each product. #58 (3y - 13)(y - 3)
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Question 66097
This question is from textbook
introducctory Algebra
:
Find each product. #58
(3y - 13)(y - 3)
This question is from textbook
introducctory Algebra
Found 2 solutions by
uma, algebrapro18
:
Answer by
uma(370)
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(3y-13)(y-3)
= 3y*y - 3y*3 - 13*y + 13*3
= 3y^2 - 9y - 13y + 39
= 3y^2 - 22y + 39
Good Luck!!!
Answer by
algebrapro18(249)
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here we use the F.O.I.L. method where that stands for First Outside Inside Last.
First -> 3y(y)
Outside -> -3y(3)
Inside -> -13(y)
Last -> 13(3)
(3y - 13)(y - 3)
=3y(y)-3y(3)-13(y)+13(3)
=3y^2-9y-13y+39
=3y^2-22y+29