SOLUTION: Find an equation of a line that has an x intercept of 6 and a y intercept of 4

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Question 650131: Find an equation of a line that has an x intercept of 6 and a y intercept of 4
Found 3 solutions by josmiceli, ewatrrr, Alan3354:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
This means the line goes through
(6,0) and (0,4)
The slope is ( change in y ) / ( change in x )
+%28+4+-+0+%29+%2F+%28+0+-+6+%29++=+-2%2F3+
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The general form is
+y+=+mx+%2B+b+
+m+ = slope
+b+ = y-intercept
------------------
+y+=+%28-2%2F3%29%2Ax+%2B+4+ answer
Here's the plot:
+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+%28-2%2F3%29%2Ax+%2B+4+%29+

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Find an equation of a line that has an x intercept of 6 ,Pt(6,0)
and a y intercept of 4 , Pt(0,4)
Using the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
(6,0)
(0,4) m = -4/6 = -2/3 || m+=%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29
Line:
y = (-2/3)x + b || Using (x,y) Ordered Pair Pt(0,4) to solve for b
4+=+%28-2%2F3%29%2A0+%2B+b
4 = b
y = (-2/3)x + 4


Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find an equation of a line that has an x intercept of 6 and a y intercept of 4
--------------
For intercepts (A,0) and (0,B) --> Bx + Ay = A*B
4x + 6y = 24
2x + 3y = 12
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Or using the 2 points (6,0) & (0,4):
Slope m = diffy/diffx = 4/-6 = -2/3
------
y = mx + b
y = (-2/3)x + 4
------
Using determinants:
|x y 1|
|6 0 1| = 0
|0 4 1|
-----
x*(0-4) - y*(6-0) + 1*(24-0) = 0
-4x - 6y + 24 = 0
2x + 3y = 12
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The 1st method is quicker, but the other 2 work for any 2 points, not just intercepts.