SOLUTION: Find an equation of the line that satisfies the given conditions. Through (5, 6); slope :2/3

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Question 647903: Find an equation of the line that satisfies the given conditions.
Through (5, 6); slope :2/3

Answer by Algebraic(50) About Me  (Show Source):
You can put this solution on YOUR website!
When you are given the slope of a line and a point on that line and are asked to find the equation of the line itself, we use the 'point-slope' formula.
The point slope formula is as follows:
y - y1 = m( x - x1 )
You replace x1 with the 'x' coordinate from the point given, y1 with the 'y' coordinate from the point given, and 'm' with the slope given.
Step 1: Let's begin by substituting what we have into the point-slope formula
Point-slope formula: y - y1 = m( x - x1 )
Point given: (5,6)
Slope given: m = 2/3
%28y-6%29+=+%282%2F3%29%28x-5%29
Step 2: Distribute the (2/3) to everything in the parenthesis
%28y-6%29+=+%282%2F3%29%28x-5%29
%28y-6%29+=+%282x%2F3%29-10%2F3
Step 3: Combine like terms by adding 6 to both sides to get 'y' by itself
%28y-6%29+=+%282x%2F3%29-10%2F3
%28y%29+=+%282x%2F3%29-10%2F3+%2B+6%2F1
Step 4: Find the LCD so you can add the fractions together. The least common denominator here is '3' because the least number that both fractions can go into is '3'
%28y%29+=+%282x%2F3%29-10%2F3+%2B+6%2F1
Step 5: Multiply (6/1) to 3 on both the numerator and denominator to be able to add the fractions
%28y%29+=+%282x%2F3%29-10%2F3+%2B+%286%2F1%29%283%2F3%29
%28y%29+=+%282x%2F3%29-10%2F3+%2B+18%2F3
Step 6: Add the fractions because they have the same denominators now
%28y%29+=+%282x%2F3%29-10%2F3+%2B+18%2F3
%28y%29+=+%282x%2F3%29%2B8%2F3
The equation of the line is %28y%29+=+%282x%2F3%29%2B8%2F3